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International Macroeconomics and Finance: Theory and Empirical Methods Phần 3 docx
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Mô tả chi tiết
2.7. FILTERING 69
Now let λò ∼ U[0, π]
29. Imagine that we take a draw from this distribu-
-1.5
-1
-0.5
0
0.5
1
1.5
0 0.4 0.8 1.2 1.6 2 2.4 2.8 3.2 3.6 4 4.4 4.8 5.2 5.6 6
Figure 2.2: π/2Phase shift. Solid: cos(t), Dashed: cos(t + π/2).
tion. Let the realization be λ, and form the time-series
qt = a cos(ωt + λ). (2.100)
Once λ is realized, qt is a deterministic function with periodicity 2π
ω and
phase shift λ but qt is a random function ex ante. We will need the
following two basic trigonometric relations.
Two useful trigonometric relations. Let b and c be constants, and i be
the imaginary number where i
2 = −1. Then
cos(b + c) = cos(b) cos(c) − sin(b) sin(c) (2.101)
eib = cos(b) + isin(b) (2.102)
(2.102) is known as de Moivreís theorem. You can rearrange it to get
cos(b) = (eib + e−ib)
2 , and sin(b) = (eib − e−ib)
2i . (2.103)
29You only need to worry about the interval [0, π] because the cosine function is
symmetric about zeroócos(x) = cos(−x) for 0 ≤ x ≤ π
70 CHAPTER 2. SOME USEFUL TIME-SERIES METHODS
Now let b = ωt and c = λ and use (2.101) to represent (2.100) as
qt = a cos(ωt + λ)
= cos(ωt)[a cos(λ)] − sin(ωt)[a sin(λ)].
Next, build the time-series qt = q1t +q2t from the two sub-series q1t and
q2t, where for j = 1, 2
qjt = cos(ωjt)[aj cos(λj )] − sin(ωjt)[aj sin(λj)],
and ω1 < ω2. The result is a periodic function which is displayed on
the left side of Figure 2.3.
-1
-0.8
-0.6
-0.4
-0.2
0
0.2
0.4
0.6
0.8
1
1 6 11 16 21 26 31 36
-30
-20
-10
0
10
20
30
1 6 11 16 21 26 31 36
Figure 2.3: For 0 ≤ ω1 < ··· < ωN ≤ π, qt = PN
j=1 qjt, where qjt =
cos(ωj t)[aj cos(λj)] − sin(ωj t)[aj sin(λj)]. Left panel: N = 2. Right
panel: N = 1000
The composite process with N = 2 is clearly deterministic but if
you build up the analogous series with N = 100 of these components,
as shown in the right panel of Figure 2.3, the series begins to look like
a random process. It turns out that any stationary random process can
be arbitrarily well approximated in this fashion letting N → ∞.
2.7. FILTERING 71
To summarize at this point, for sufficiently large number N of these
underlying periodic components, we can represent a time-series qt as
qt = X
N
j=1
cos(ωj t)uj − sin(ωj t)vj, (2.104)
where uj = aj cos(λj ) and vj = aj sin(λj), E(u2
i) = σ2
i , E(uiuj)=0,
i 6= j, E(v2
i) = σ2
i , E(vivj)=0, i 6= j.
Now suppose that E(uivj) = 0 for all i, j and let N → ∞.
30 You
are carving the interval into successively more subintervals and are
cramming more ωj into the interval [0, π]. Since each uj and vj is
associated with an ωj , in the limit, write u(ω) and v(ω) as functions
of ω. For future reference, notice that because cos(−a) = cos(a), we
have u(−ω) = u(ω) whereas because sin(−a) = − sin(a), you have
v(−ω) = −v(ω). The limit of sums of the areas in these intervals is the
integral
qt =
Z π
0
cos(ωt)du(ω) − sin(ωt)dv(ω). (2.105)
Using (2.103), (2.105) can be represented as
qt =
Z π
0
eiωt + e−iωt
2
du(ω) −
Z π
0
eiωt − e−iωt
2i
dv(ω)
| {z }
(a)
. (2.106)
Let dz(ω) = 1
2 [du(ω) + idv(ω)]. The second integral labeled (a) can be
simplified as ⇐(49)
Z π
0
eiωt − e−iωt
2i
dv(ω) = Z π
0
eiωt − e−iωt
2i
Ã
2dz(ω) − du(ω)
i
!
=
Z π
0
e−iωt − eiωt
2 (2dz(ω) − du(ω))
=
Z π
0
(e−iωt − eiωt
)dz(ω) + Z π
0
eiωt − e−iωt
2
du(ω).
Substitute this last result back into (2.106) and cancel terms to get ⇐(50)
30This is in fact not true because E(uivi) 6= 0, but as we let N → ∞, the
importance of these terms become negligible.