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Tài liệu Introduction To Statics And Dynamics P2 doc
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Mô tả chi tiết

2.2. The dot product of two vectors 23

2.2 The dot product of two vectors

The dot product is used to project a vector in a given direction, to reduce a vector

to components, to reduce vector equations to scalar equations, to define work and

power, and to help solve geometry problems.

The dot product of two vectors

A and

B is written

A ·

B (pronounced ‘A dot B’).

The dot product of

A and

B is the product of the magnitudes of the two vectors times

a number that expresses the degree to which

A and

B are parallel: cos θAB, where

θAB is the angle between

A and

B. That is,

B

A

θAB

B

A

cosθAB

cosθAB

Figure 2.17: The dot product of

A and

B is a scalar and so is not easily drawn. It is

given by

A ·

B = AB cos θAB which is A

times the projection of

B in the A direction

and also B times the projection of

A in the

B direction.

(Filename:tfigure1.11)

A ·

B def = |

A| |

B| cos θAB

which is sometimes written more concisely as

A ·

B = AB cos θ. One special case

is when cos θAB = 1,

A and

B are parallel, and

A ·

B = AB. Another is when

cos θAB = 0,

A and

B are perpendicular, and

A ·

B = 0.

1

1 If you don’t know, almost without

a thought, that cos 0 = 1, cos π/2 =

0,sin 0 = 0, and sin π/2 = 1 now is as

good a time as any to draw as many trian￾gles and unit circles as it takes to cement

these special cases into your head.

The dot product of two vectors is a scalar. So the dot product is sometimes called

the scalar product. Using the geometric definition of dot product, and the rules for

vector addition we have already discussed, you can convince yourself of (or believe)

the following properties of dot products.

A ·

B =

B ·

A commutative law,

AB cos θ = B A cos θ

• (a

A) ·

B =

A · (a

B) = a(

A ·

B) a distributive law,

(a A)B cos θ = A(aB) cos θ

A · (

B +

C) =

A ·

B +

A ·

C another distributive law,

the projection of

B +

C onto

A is the

sum of the two separate projections

A ·

B = 0 if

A ⊥

B perpendicular vectors have zero for

a dot product, AB cos π/2 = 0

A ·

B = |

A||

B| if

A 

B parallel vectors have the product of

their magnitudes for a dot product,

AB cos 0 = AB. In particular,

A ·

A = A2 or |

A| = √

A ·

A

• ıˆ · ıˆ = ˆ · ˆ = kˆ · kˆ = 1,

ıˆ · ˆ = ˆ · kˆ = kˆ · ıˆ = 0

The standard base vectors used with

cartesian coordinates are unit vectors

and they are perpendicular to each

other. In math language they are ‘or￾thonormal.’

• ıˆ

 · ıˆ

 = ˆ

 · ˆ

 = kˆ



· kˆ



= 1,

ıˆ

 · ˆ

 = ˆ

 · kˆ



= kˆ



· ıˆ

 = 0

The standard crooked base vectors

are orthonormal.

The identities above lead to the following equivalent ways of expressing the dot

product of

A and

B (see box 2.2 on page 24 to see how the component formula

follows from the geometric definition above):

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