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Math test english 9 ppt
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Practice Questions Answers and Explanations
1. Choice a is correct. The word and indicates a decimal point. Therefore, the decimal point should go
after five hundred twelve and before sixteen thousandths. The number 16 must end in the thousandths
place, which is three digits to the right of the decimal. The correct answer is 512.016.
Choice b is “five hundred twelve and sixteen hundredths.”
Choice c is “five hundred twelve thousand, one hundred sixty.”
Choice d is “fifty one and two hundred sixteen thousandths.”
Choice e is “five hundred twelve and sixteen ten thousandths.”
2. Choice f is correct. First, change the fractional parts of the problem to have the common denominator
of 12.
41
4
2
− 11
9
2
Subtract the numerators. Since 4 is less than 9, you must borrow one whole from the whole number 4.
This means that you are adding
1
1
2
2
to the first fraction.
3
1
1
6
2
− 11
9
2
.
Subtract the fractional parts then the whole numbers. The final answer is 21
7
2
.
3. Choice b is correct. The correct order of operations must be used to simplify the expression. You may
remember this as PEMDAS or “Please Excuse My Dear Aunt Sally.” The P stands for parentheses or any
grouping symbol. Absolute value is a grouping symbol, so it will be done first.
|−8| + 4 × 23 =
8 + 4 × 23
Next, perform the exponent part.
8 + 4 × 8
Then, the multiplication.
8 + 32
Last, the addition.
The final answer is 40.
4. Choice g is correct. This problem can be approached a couple of different ways. The simplest way
might be to look at multiples of 4 and 5 until the multiples add to 18. If both 4 and 5 are multiplied by
2, they become 8 and 10. 8 plus 10 is 18. Therefore, there are 8 boys and 10 girls in the class.
The problem can also be done with an equation.
4x + 5x = 18
When solved, x = 2. Multiply 4 by 2 to find that there are 8 boys.
–ACT MATH TEST PRACTICE–
184