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KT T 7 Chuong 4(15'''')
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Mô tả chi tiết
Tröôøng THCS haûi Nam
Hoï vaø teân:……………..
Lôùp 7B
Kieåm tra moân ñaïi soá 7
2 - Thôøi gian 15’
Ngaøy thaùng 4 naêm 2009
§Ò lÎ: Cho 2 ®a thøc: A = -5x3
+ 4 x2y + 7xy + 10x3
+ 3y5
- 14xy + 6xy2
B = -3x2
y2 - 5 xy2
+ 6xy - 3x2y + 6x2
y2
+ 2x3
a) Thu gän 2 ®a thøc A vµ B.
b) TÝnh: A + B vµ A - B
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Tröôøng THCS haûi Nam
Hoï vaø teân:……………..
Lôùp 7B
Kieåm tra moân ñaïi soá 7
2-Thôøi gian 15’
Ngaøy thaùng 4 naêm 2009
§Ò ch½n: Cho 2 ®a thøc: f(x) = -10x - x2
+ 3x5
+ 2x4
+ 4x3
+ 1- 4x4 + 5x
G(x) = x2 - 4x3
-2 x2
- 3x + 2x4
- 1+ 6x
a) Thu gän råi s¾p xÕp 2 ®a thøc f(x) vµ g(x) theo lòy thõa gi¶m dÇn cña biÕn.
b) TÝnh: f(x) + g(x) theo hµng ngang.
f(x) - g(x) theo cét däc
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